Tutors Answer Your Questions about Exponential-and-logarithmic-functions (FREE)
Question 903135: Hello i have this problem Solve: 2^(x+3)=2^5
I've worked it to
LN(2^(x+3)) = LN(2^5)
x+3*LN(2)=5*LN(2)
x= 5LN(2)/3LN(2)
Hower this answer does not match up any of the possible answers i have to choose from:
a) 2log(x+2)+log(x-1)
b)log 3
c)log(x^2+2)-log(x-1)
d)log(x+1)
Someone help. Thanks.
Click here to see answer by Alan3354(69443)  |
Question 906984: Urgent I have tried everything I am not good with logarithms Please help.
This is question about Photic Zone.
The exponential function is I=Isub0e^-kx Isub0= 1000 foot candles so I=
depth of the water is x= depth in feet
What is the intensity of light at the depth of 10 feet? Round answer to one decimal place.
Click here to see answer by Alan3354(69443)  |
Question 912638: -3 + (8+2x)^(5/4)=29
Not exactly sure which section this belongs to, but what's throwing me off is the fractional power. I got to (8+2x)^(5/4) = 32, and I tried to simplify it by putting 2x + 8 to the 5th power, and then to the fourth root, but I was still confused on how to solve from there. I'd really appreciate any hints or help with this, it's really mind boggling to me.
Click here to see answer by excellentsolutionas(12)  |
Question 912667: -3 + (8+2x)^(5/4)=29
Not exactly sure which section this belongs to, but what's throwing me off is the fractional power. I got to (8+2x)^(5/4) = 32, and I tried to simplify it by putting 2x + 8 to the 5th power, and then to the fourth root, but I was still confused on how to solve from there. I'd really appreciate any hints or help with this, it's really mind boggling to me.
Click here to see answer by josgarithmetic(39620) |
Question 913131: Solve 16^(x) - 4^(x-1) - 3 = 0
By looking at the problem it seems to me this is an exponential equation of the quadratic flavor which can somehow can be rewritten in the ax^2 + bX + c = 0 fashion. But I don't get much farther than turning the 16^x into a (4^x)^2. This has stumped me. I've tried different things and at the end I have to resort to using the quadratic formula to factor this bugger, but it never results close to the actual answer of logbase4(-2 + √7)
Any help is much appreciated!
Click here to see answer by jim_thompson5910(35256) |
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