Tutors Answer Your Questions about Exponential-and-logarithmic-functions (FREE)
Question 859696: Please help me solve the following equation:
2(3)^2x – 10 = 0
I've got just as much information on it as you. I know logs come into play to it somehow. I got as far as:
2(3)^2x – 10 = 0
6^2x=10
Log6 10=2x
7.7815125=2x
7.7815125/2=x
x=3.89075625
But after trying to double check with the original equation... well, I was way off. I'd appreciate it also if someone could help me understand where I went wrong.
Thanks!
Click here to see answer by Alan3354(69443)   |
Question 860090: Hello,
Please help me with the following as I am completely stuck on it and google isn't helping me find methods involving a "y" variable.
"Given that 2^y = 16^(x – 3) and 3^(y+2) = 27^x, find the value of x + y"
Thank you!!
Click here to see answer by josmiceli(19441)  |
Question 860090: Hello,
Please help me with the following as I am completely stuck on it and google isn't helping me find methods involving a "y" variable.
"Given that 2^y = 16^(x – 3) and 3^(y+2) = 27^x, find the value of x + y"
Thank you!!
Click here to see answer by mananth(16946)  |
Question 860321: I am struggling to do my homework, it's asking me to write the inverse of a one-to-one function using the notation f^-1(x). The original equation is f(x)=x^3.
I thought I would multiply the cube with the power of 1/3 so the exponent will have a result of 1 but I figured that if I do that the left side of the equation will have an exponent of 1/3, so I am not sure what to do, please help me on this problem. Thank you.
Click here to see answer by josgarithmetic(39620) |
Question 861695: Question: 9^2x *27^x^2=3^-1, I am trying to find x.
I tried to change base 9 to base 3 and multiplied the exponent by 2 and I got 4x then I changed base 27 to base 3 and multiplied the exponent by 3 but I'm not sure if I'm correct so far.
Click here to see answer by mananth(16946) |
Question 862105: In 2010, the population of a country was 72 million and growing at a rate of 1.8% per year. Assuming the percentage growth rate remains constant, express the population, P, in millions, as a function of t, the number of years after 2010.
P=f(t)=
Click here to see answer by josgarithmetic(39620) |
Question 862226: The number of bacteria increased exponentially. At first there were 300. Six hours later there were 900. How many bacteria will there be in twelve hours?
This is what I did, solve for k? I got k= .18 by using this formula, 900=300e^k(6)
I am having trouble solving this. I get 2601 the solutions manual has 2700.
Click here to see answer by josgarithmetic(39620) |
Question 862830: the fox population in a certain region has a continuous growth rate of 5% per year. It is estimated that the population in the year 2000 was 9100.
a)find the function that models the population t years after 2000(t=0 for 2000) your answer is P(t)=
b)use the function from part a to estimate the fox population in the year 2008. answer must be an integer.
I am using the formula A=Pe^rt
P=2000
r=.05
t=8years
however I see I am to solve for P, but can't find any examples of how to do this.
Click here to see answer by ewatrrr(24785)  |
Question 862833: The fox population in a certain region has a continuous growth rate of 5 percent per year. It is estimated that the population in the year 2000 was 9100.
(a) Find a function that models the population t years after 2000 (t=0 for 2000).
Your answer is P(t) =
(b) Use the function from part (a) to estimate the fox population in the year 2008.
Your answer is (the answer must be an integer)
Click here to see answer by josmiceli(19441) |
Question 862847: Train A leaves Montreal heading to BC . Train B leaves at 9 am on a parallel track also heading to BC. The rate of train A is 80 km/ hour and rate of train B is 100 km/hour . How long will it take train B to catch up with train A?
Can you please help me out? Thanks so much in advance:)
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 864593: Solve each equation for x thus expressing x as a log function of y
a) y = 5(2)^x
b) y = 1.3(10)^x
c) y = 8.2(1.3)^x
d) y = 6.4(1/2)^x
e) y = 3.5(2.7)^x
f) y = 2.75(2/3)^x
Can you please help me out? Thanks so much in advance:)
Click here to see answer by Alan3354(69443) |
Question 864782: An investment of $500 at 8% per annum compounded annually grows to A$ in n years
a) solve this equation for n
b) so expressing n as a log function of A
calculate the value of n for each value of A 1) A = 1250 2) A = 350
c) graph the function in part a for 0
d) state the domain and range
Can you please help me out ? Thanks so much in advance:)
Click here to see answer by stanbon(75887) |
Question 864776: Solve each equation for x thus expressing x as a log function of y
a) y = 1.3(10)^x
b) y = 8.2(1.3)^x
c) y = 6.4(1/2)^x
d) y = 3.5(2.7)^x
e) y = 2.75(2/3)^x
Can you please help me out? Thanks so much in advance:)
Click here to see answer by Alan3354(69443) |
Question 864823: Please help with this question. It's too complicated and I don't know how to do this problem. Thank you very much.
Use properties of logarithms to expand the logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions.
log [(10x 5^3square root of 6-x)/ 7(x+6)^2]
Click here to see answer by lwsshak3(11628) |
Question 864871: Hi!
Please help! On my worksheet it says to solve this question:
logBasec(x-1)-logBasea(x+6)=logBasea(x-2)-logBasea(x+3)
I'm not sure how to do this - also, how do I 'solve' if there are two variables? Could someone show me how to do this step-by-step? Thank you so much!
Click here to see answer by stanbon(75887) |
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