Tutors Answer Your Questions about Exponential-and-logarithmic-functions (FREE)
Question 563670: Please help with this. I can't understand the way my teacher is trying to explain.
Let "b" be a number such that log(b)3 = 1.5 and log(b)5=2.2
evaluate the following:
1. log (b)5/3
2. log (b)3b^2
3. log (b)45
4. log (b)(b/15)
Thank you so much for your help
Click here to see answer by josmiceli(19441)  |
Question 563705: Please help with this. I can't understand the way my teacher is trying to explain.
Let "b" be a number such that log(b)3 = 1.5 and log(b)5=2.2
evaluate the following:
1. log (b)15
2. log (b).6
3. log (b)125
4. log (b)(^3sqrt(3))^7
Thank you so much for your help
Click here to see answer by Alan3354(69443)  |
Question 563705: Please help with this. I can't understand the way my teacher is trying to explain.
Let "b" be a number such that log(b)3 = 1.5 and log(b)5=2.2
evaluate the following:
1. log (b)15
2. log (b).6
3. log (b)125
4. log (b)(^3sqrt(3))^7
Thank you so much for your help
Click here to see answer by Tatiana_Stebko(1539)  |
Question 565529: Please Help with this. My teacher did not explain how to do these problems.
Use the formula D^3 = 216T^2
1. Find what happens to the duration of a storm if its diameter is doubled.
2. determine how long a storm will last if it has a diameter of 10 mi.
Thank you so much.
Click here to see answer by stanbon(75887) |
Question 467405: A grandmother is looking for a plan to finance her new grandchild’s college education. She has $25,000 to invest. Search the internet and locate a long-range investment plan, CD, Savings Bond, etc, for the grandmother. The plan is to earn compound interest.
Calculate the future value of the investment. You must use the advertised interest rate,which is 3.40% the number of compounding periods per year,which and the time the funds will be invested. If you are not given the number of compounding periods a year, make it up.
The principal is $25,000. This is P.
Research the annual interest rate for your investment. This is r.
State the time in years for the investment (as in when the new grandchild will be attending college) which is 18. This is t.
State the number of compounding periods per year.2, This is n.
Model the future value of Grandma’s investment as an exponential function, with time as the independent variable: F(t) = P(1 + r/n) nt
State the future value of Grandma’s investment.
Use the internet or library resources to find the average cost of a college education today; will grandma’s investment be able to cover the cost in today’s dollars; what about in the future?
Summarize your findings in writing using proper style and grammar.
Click here to see answer by deeakram(1) |
Question 566011: Potassium 42 has a decay rate of approximately 5.5% per hour, assuming an exponential decay model, fine the number of hours it will take for the original quantity of potassium 42 to b halved?
Click here to see answer by KMST(5328)  |
Question 566148: I am having difficulty comprehending how this is done. Please Help!
Use the formula v= 4/3 pi r^3
1. If the radius of a ball is twice that of another, how many times as big is its volume?
2. If the volume is twice that if a blue ball, how many times as big is its radius?
Thank you
Is
Click here to see answer by Alan3354(69443)  |
Question 568663: I'm not entirely sure this is the right subject, sorry if it's not...
A substance decomposes radioactively. Its half-life is 32 years. Find the constant "k" in the decay formula.
Use this formula instead: 
y= final value
n= initial value
k= constant
t= time
e= antilogarithm
Click here to see answer by solver91311(24713)  |
Question 574650: Ok, so I just want to know the method of finding the base of a logarithm. I am given a picture of a graph; two points of a function, (3,5) and (5,9); and the asymptote: x=2 . I see that there are 6 variables for me to find, and that I am given 5 numbers to "plug" in. I see how the graph points (3,5) and (5,9) fit into the equation y=alog↓b(x-h)+k, but I don't understand how to put the asymptote into the equation or how to find base b. Is there a specific way to find base b of a graph using these?
Click here to see answer by KMST(5328)  |
Question 576749: The half-life of a radioactive substance is the time it takes for half of the substance to decay. The half-life if carbon-14 is 5700 years.
A.) write a exponential function to model the decay of a 240-my sample.
B.) explain what each value in the function model represents.
C.) to the nearest hundredth, find the amount of carbon-14 remaining after 2353 years. Explain how you found this amount.
Click here to see answer by ankor@dixie-net.com(22740)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910
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