Tutors Answer Your Questions about Exponential-and-logarithmic-functions (FREE)
Question 159131: Suppose that the number of new homes built, H, in a city over a period of time, t, is graphed on a rectangular coordinate system where time is on the horizontal axis. Suppose that the number of homes built can be modeled by an exponential function, H= p * at , where p is the number of new homes built in the first year recorded. If you were a homebuilder looking for work, would you prefer that the value of a to be between 0 and 1 or larger than 1?
Assistance is requested with the equation ... below is what has been done.
When p > 0, a > 1, t gets larger, as well as y. When 0 < a < 1, then y gets continually smaller. As a homebuilder seeking work, the preference would be to have the value of a to larger than 1 (a > 1) to ensure plenty of work.
H=500 t = 1 p = 5
f(x)/t = p*ln(a)*a^t
y/1 = 5 (1) * 1^1
1^1 = 2.72^1 (1)
(1) (2.72^1)/ 1
(1) 2.72* 1
y = 2.72
Thank you for the assistance.
Click here to see answer by stanbon(75887) |
Question 159133: Suppose that the function P = 13 + 14 ln x, represents the perecentage of inbound e-mail in the US. that is considered Spam, where x represents the number of years after 2000.
Use this model to determine in how many years(to two decimal places) it will take for the percentage to reach 95%, provided that law enforcement regarding spammers does not change.
Click here to see answer by gonzo(654) |
Question 161301: PLEASE HELP! THIS PROBLEM IS DUE AT 11 P.M. PST TONIGHT (10-9-08)!!!
Im hoping this is the right forum for this problem.
Find the solution of the exponential equation, correct to four decimal places.
8^(x / 2) = 3^(1 - x)
x =____________
Please help! Thanks guys! I appreciate the help!
Click here to see answer by stanbon(75887) |
Question 163298: Is this right? I'm not sure.
Using the table of logarithms find the value of each expression.
cube root of 100 ?
this is what I have
100 ^1/3
1/3 log 100
1/3 log 1 * 10^2
1/3 0 + 2
answer 2 That just doesn't look right. Can anybody help???
Click here to see answer by Alan3354(69443)  |
Question 165019:
An investment of $25,400 is placed into an account that earns 6.5% interest compounded quarterly. In how many years will the investment be worth twice the original amount?
I am thinking I would use the compound interest formula A = P(l + i)^n
I had set it up like below but I seem I am doing it wrong. Should I have went with 4 or 12? any help appreciated
i = 6.5%/4 = .065/4 = .01625
101600 = 25,400(1 + .01625)^n
101600 = 25400(1.01625)^n
4 = (1.01625)^n
log4 = log(1.01625)^n
log4 = n log 1.01625
log4/log1.01625 = n
86.0017 = n
86.0017/4 = 21.50004
In approx. 21.5 years , the investment will be worth $101,600.
Click here to see answer by jojo14344(1513) |
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