SOLUTION: x^2e^x = 2xe^x, find its solution set
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Question 822967
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x^2e^x = 2xe^x, find its solution set
Answer by
tommyt3rd(5050)
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x^2e^x - 2xe^x=0
(x^2-2x)e^x=0
(x-2)xe^x=0
x=0 or x=2
