SOLUTION: What is the x-coordinate, to 2 decimal places, of the vertex (i.e. turning point) of the parabola with equation y = ax^2 + bx + c where a = 32, b = -29 and c = 108?

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: What is the x-coordinate, to 2 decimal places, of the vertex (i.e. turning point) of the parabola with equation y = ax^2 + bx + c where a = 32, b = -29 and c = 108?      Log On


   

Question 984493: What is the x-coordinate, to 2 decimal places, of the vertex (i.e. turning point) of the parabola with equation
y = ax^2 + bx + c
where a = 32, b = -29 and c = 108?
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
A neat way is to work symbolically with the model equation, complete the square and put into standard form, and you can read the symbolic form for the vertex from this transformed equation. THEN substitute your values for a, b, and c. Your textbook may have this derivation for you.

Say if you have trouble with this now.