SOLUTION: my equation is: log1/7(x^2+x)-log1/7(x^2-x)=-1 i got x=-4/3 is this correct?

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: my equation is: log1/7(x^2+x)-log1/7(x^2-x)=-1 i got x=-4/3 is this correct?       Log On


   

Question 976516: my equation is:
log1/7(x^2+x)-log1/7(x^2-x)=-1

i got x=-4/3
is this correct?
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


No. Where did you get the minus sign? Extra credit: Why did you exclude x = 0?

John

My calculator said it, I believe it, that settles it