SOLUTION: Find the equation of the tangent to the graph at the indicated point f(x)=x^2-6x a= -5 y=

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Find the equation of the tangent to the graph at the indicated point f(x)=x^2-6x a= -5 y=      Log On


   

Question 946753: Find the equation of the tangent to the graph at the indicated point
f(x)=x^2-6x
a= -5
y=
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The slope of the tangent is equal to the value of the derivative at the point.
f%28x%29=x%5E2-6x
df%2Fdx=2x-6
So at x=-5
m=2%28-5%29-6
m=-16
So then,
f%28-5%29=25%2B30=55
and
y-55=-16%28x-%28-5%29%29
y-55=-16%28x%2B5%29
y-55=-16x-80
highlight%28y=-16x-25%29
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graph%28300%2C300%2C-10%2C10%2C-10%2C90%2Cx%5E2-6x%2C-16x-25%29