SOLUTION: How would I find the asymptote of y = -5^x or y = -24(1/2)^X. Please explain in detail how I would and show the steps you took to find it!

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: How would I find the asymptote of y = -5^x or y = -24(1/2)^X. Please explain in detail how I would and show the steps you took to find it!      Log On


   



Question 944595: How would I find the asymptote of y = -5^x or y = -24(1/2)^X. Please explain in detail how I would and show the steps you took to find it!
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
find the asymptote of
y = -5^x
------
5^x approaches zero, but never reaches zero, as x approaches zero
The negative does not change the limit.
Asymptote:: y = 0
Graph::
graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C-5%5Ex%29
======================

y = -24(1/2)^X
(1/2)^x approaches 0 as x approaches infinity.
The -24 does not change the limit.
Asymptote:: y = 0
Graph::
graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C-24%281%2F2%29%5Ex%29
=============================
Cheers,
Stan H.
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