SOLUTION: Please help with the problem:
A satellite has a radioactive isotope for its power supply. The power output in watts after elapsed time t in days since powering up is given by Pt
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: Please help with the problem:
A satellite has a radioactive isotope for its power supply. The power output in watts after elapsed time t in days since powering up is given by Pt
Log On
Question 930450: Please help with the problem:
A satellite has a radioactive isotope for its power supply. The power output in watts after elapsed time t in days since powering up is given by Pt=50e^(-t/2035. The onboard equipment requires 10 watts of power to operate properly. What is the operational life (in years) of the satellite?
Thank You
You can put this solution on YOUR website! The power output in watts after elapsed time t in days since powering up is given by Pt=50e^(-t/2035.
The onboard equipment requires 10 watts of power to operate properly.
What is the operational life (in years) of the satellite?
:
Find t when Pt = 10
50*e^(-t/2035) = 10
divide both sides by 50
e^(-t/2035) = .2
Find the nat log of both sides
ln(e^(-t/2035)) = ln(.2)
the log equiv of exponents ln(e) = ln(.2)
the ln of e = 1 so we have = -1.61
multiply both sides by -2035
t = 3275.2 days
which is
3275.2/365 = 8.97 ~ 9 years is the life of the satellite
:
;
You can check this for yourself on your calc
enter: 50*e^(-3275/2035)
