SOLUTION: Find the negative value for x such that 2^log base4(1/64) +x^2 =73/8 I would appreciate any help! Thank you!

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Find the negative value for x such that 2^log base4(1/64) +x^2 =73/8 I would appreciate any help! Thank you!      Log On


   

Question 929769: Find the negative value for x such that 2^log base4(1/64) +x^2 =73/8
I would appreciate any help!
Thank you!
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
2^log base4(1/64) = 2^(-3.0) = 1/(2^3) = 1/8
1/8 +x^2 = 73/8
multiply 8 times both sides of =
1 +8x^2 = 73
8x^2 = 72
x^2 = 9
x = 3 or -3
you want the -3