SOLUTION: I am so bad with these can someone help me solve this problem:
x = log7(1/49)
The 7 is slightly below the log not beside it. I hope that helps.
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: I am so bad with these can someone help me solve this problem:
x = log7(1/49)
The 7 is slightly below the log not beside it. I hope that helps.
Log On
Question 91336: I am so bad with these can someone help me solve this problem:
x = log7(1/49)
The 7 is slightly below the log not beside it. I hope that helps. Answer by tutor_paul(519) (Show Source):
You can put this solution on YOUR website! x = log7(1/49)
==============
Think of a logarithm in terms of what it means in exponent form.
The "7" is the base, the "1/49" is the answer, and the logarithm is the exponent. In other words, you problem can be re-written as:
When written in this form, you can easily see that
That is your answer.
Good luck,
tutor_paul@yahoo.com
