SOLUTION: Pls help me solve this, Integrate sec^2 x/(2+tanx)(3-tanx) dx (Hint: t=tanx) Thank you so much...:)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Pls help me solve this, Integrate sec^2 x/(2+tanx)(3-tanx) dx (Hint: t=tanx) Thank you so much...:)      Log On


   



Question 903737: Pls help me solve this,
Integrate sec^2 x/(2+tanx)(3-tanx) dx
(Hint: t=tanx)
Thank you so much...:)

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
int%28%28sec%5E2x%2Adx%29%2F%28%282%2Btanx%29%283-tanx%29%29%29

[Your hint says to use t = tanx, but most teachers and books use
the letter u rather than the letter t, so I'll use u = tanx, but 
you can substitute t everywhere I have u if you like.]

let u+=+tanx, then du+=+sec%5E2xdx, dx=du%2F%28sec%5E2x%29

int%28%28sec%5E2x%2A%28du%2F%28sec%5E2x%29%29%29%2F%28%282%2Bu%29%283-u%29%29%29



int%28du%2F%28%282%2Bu%29%283-u%29%29%29

Break 1%2F%28%282%2Bu%29%283-u%29%29 into partial fractions:

But before doing that let's get the denominators in descending 
powers of u.
[That isn't absolutely necessary but it is customary because it 
keeps things more orderly.  Also it is customary to get the 
leading term positive, which I will do on the second term]

2+u = u+2      <--first term, just turn it around

3-u = -u+3 = -(u-3)    <--second term, factor out -1

1%2F%28%28u%2B2%29%28-%28u-3%29%29%29

%28-1%29%2F%28%28u%2B2%29%28u-3%29%29

%28-1%29%2F%28%28u%2B2%29%28u-3%29%29%22%22=%22%22A%2F%282%2Bu%29%2BB%2F%28u-3%29

-1%22%22=%22%22A%28u-3%29%2BB%28u%2B2%29

This has to be identically true for all u so substitute u=3
to make the first term on the right become 0

-1%22%22=%22%22A%283-3%29%2BB%283%2B2%29

-1%22%22=%22%220%2B5B

-1%2F5%22%22=%22%22B

substitute u=-2 to make the second term on the right become 0:

-1%22%22=%22%22A%28-2-3%29%29%2BB%28-2%2B2%29

-1%22%22=%22%22A%28-5%29%2BB%280%29%29

-1%22%22=%22%22A%28-5%29%2B0%29

1%2F5%22%22=%22%22A

So our integral is now

int%28du%2F%28%282%2Bu%29%283-u%29%29%29 %22%22=%22%22 expr%281%2F5%29%2Aint%28+du%2F%28u%2B2%29+%29%22%22-%22%22expr%281%2F5%29%2Aint%28du%2F%28u-3%29%29+++%22%22=%22%22

expr%281%2F5%29%2Aln%28u%2B2%29-expr%281%2F5%29%2Aln%28u-3%29%2BC%22%22=%22%22expr%281%2F5%29%2A%28ln%28u%2B2%29%5E%22%22-ln%28u-3%29%5E%22%22%29%2BC%22%22=%22%22

Substitute u+=+tanx

expr%281%2F5%29%2A%28ln%28tanx%2B2%29%5E%22%22-ln%28tanx-3%29%5E%22%22%29%2BC

Edwin