SOLUTION: Hello, Can someone help me with this equation. logx1331=3. I am not quite sure how to solve this equation. Please help. Thank you in advance.

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Hello, Can someone help me with this equation. logx1331=3. I am not quite sure how to solve this equation. Please help. Thank you in advance.       Log On


   

Question 895066: Hello, Can someone help me with this equation.
logx1331=3. I am not quite sure how to solve this equation. Please help. Thank you in advance.
Found 2 solutions by josgarithmetic, Edwin McCravy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Try again.
What is the base? What is the function's input?

Are you asking for log%28x%2C1331%29=3
Or
log%2810%2Cx%2A1331%29=3
OR
Something else?

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
Learn how to convert log equations to exponential equations and
vice-versa:

These two equations are always equivalent:

   LOG EQUATION             EXPONENTIAL EQUATION

       logBA = C              BC = A 


Therefore the log equation

logx1331 = 3 

is equivalent to the exponential equation:

x3 = 1331

Take the cube root of both sides

x = root%283%2C1331%29

x = 11

Edwin