SOLUTION: log (x-4) = log 32 - log x log (x+1) + 2*log (x) = log (x^2+8)

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Question 885046: log (x-4) = log 32 - log x
log (x+1) + 2*log (x) = log (x^2+8)
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
log (x-4) = log 32 - log x
log (x+1) + 2*log (x) = log (x^2+8)


log (x-4) = log 32 - log x

Simplifies to: (x - 8)(x + 4) = 0

highlight_green%28highlight_green%28x+=+8%29%29      OR      x = - 4 (ignore)



log (x+1) + 2*log (x) = log (x^2+8)

Simplifies to:  x%5E3+=+8

highlight_green%28highlight_green%28x+=+2%29%29    



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