Question 8411: How do you work this problem:
Solve for x in this equation:
(2/3)^x = 9/4
Answer by khwang(438)   (Show Source):
You can put this solution on YOUR website! (2/3)^x = 9/4
Since 9/4 = (3/2)^2 and
(3/2) = (2/3)^(-1)
So, 9/4 = (3/2)^2 = [(2/3)^(-1)]^2 = (2/3)^(-2)
and we get (2/3)^x = (2/3)^(-2)
Therefore ,by comparing the exponent,
we obtain x = -2.
(or by taking the logarithm with base 2/3 on
both sides]
Kenny
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