SOLUTION: log(x^2-x-12)+2=log(x-4)

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Question 818727: log(x^2-x-12)+2=log(x-4)

Found 2 solutions by jhunjiro, MathTherapy:
Answer by jhunjiro(67) About Me  (Show Source):
You can put this solution on YOUR website!

Solution:
log(x^2-x-12)+2=log(x-4)
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log(x^2-x-12)- log(x-4) +2 = 0
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log(x^2-x-12)- log(x-4) = -2
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x^2-x-12 = (x-4)(x+3)
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log((x-4)(x+3))- log(x-4) = -2
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log x - log y = log x/y
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log [(x-4)(x+3)/(x-4)] = -2
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log (x+3) = -2
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b^y = x
b=10
y=-2
x=(x+3)
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10^-2 = x+3
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1/100 = x+3
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x = 1/100 - 3
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x = 1/100 - 300/100
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x= -(299/100) or x= -2.99
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Final Answer:
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x= -(299/100) or x= -2.99









Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

log(x^2-x-12)+2=log(x-4)


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