SOLUTION: 28(132^(39x - 20)) = 12481 A 2.755 B0.345 C1.675 D2.345 E 0.545 F 4.235 5e^(2.1x - 2) = 14 A 1.443 B2.543 C5.343 D2.434 E 1.343 F 0.443

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: 28(132^(39x - 20)) = 12481 A 2.755 B0.345 C1.675 D2.345 E 0.545 F 4.235 5e^(2.1x - 2) = 14 A 1.443 B2.543 C5.343 D2.434 E 1.343 F 0.443       Log On


   

Question 769860: 28(132^(39x - 20)) = 12481
A 2.755
B0.345
C1.675
D2.345
E 0.545
F 4.235

5e^(2.1x - 2) = 14
A 1.443
B2.543
C5.343
D2.434
E 1.343
F 0.443
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
28(132^(39x - 20)) = 12481
(132^(39x - 20)) = 12481/28=445.75
(39x-20)=log(445.75)/log(132)
39x=20+log(445.75)/log(132)
x=0.545 ans: E
..
5e^(2.1x - 2) = 14
e^(2.1x - 2) = 14/5
(2.1x-2)lne=ln(14/5)
(2.1x-2)=ln(14/5)
2.1x=ln(14/5)+2
1.443 Ans A