SOLUTION: two questions and answers:
a) integrate 3^x
answer: 3^x/In(3)
b) find the exact area enclosed by the curve y=e^3x - 2, the x-axis and the lines x=0 and x=1
answer: 4In(2)/3 + e
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: two questions and answers:
a) integrate 3^x
answer: 3^x/In(3)
b) find the exact area enclosed by the curve y=e^3x - 2, the x-axis and the lines x=0 and x=1
answer: 4In(2)/3 + e
Log On
Question 758447: two questions and answers:
a) integrate 3^x
answer: 3^x/In(3)
b) find the exact area enclosed by the curve y=e^3x - 2, the x-axis and the lines x=0 and x=1
answer: 4In(2)/3 + e^3/3 - 3
my question is, how do you get to these answers? can you please show me step by step. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! two questions and answers:
a) integrate 3^x
-------
= answer
answer: 3^x/In(3)
==============
b) find the exact area enclosed by the curve y=e^3x - 2, the x-axis and the lines x=0 and x=1 Ignore the constant of integration
=============
What is the exponent of e? 3x? or 3x-2?
answer: 4In(2)/3 + e^3/3 - 3 =~ 4.619375
