SOLUTION: log5(4x +1) = log5 (2x+7)
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Question 756786
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log5(4x +1) = log5 (2x+7)
Answer by
tommyt3rd(5050)
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log5(4x +1) = log5 (2x+7)
5^log5(4x +1) =5^log5 (2x+7)
4x+1=2x+7
2x=6
x=3