SOLUTION: 4^2x+1 = 671 Thank you for your help!

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: 4^2x+1 = 671 Thank you for your help!      Log On


   



Question 750798: 4^2x+1 = 671

Thank you for your help!

Answer by timvanswearingen(106) About Me  (Show Source):
You can put this solution on YOUR website!
4%5E%282x%29%2B1+=+671
Subtract 1 from both sides:
4%5E%282x%29=670
Take log base 4 of both sides. All you are left with on the left side is 2x. So 2x= log base 4 of 670. Using a change of base formula, 2x= (log 670) / (log 4). Divide both sides by 2, x is about 2.347.