SOLUTION: (3x^3y^2) (2X^4y) When I multiply x^3*x^4= X^12 Y^2*Y=y^2 do I still mulity the 3 and the 2 together ? Would the answer be 6x^12Y^2? Thank you

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: (3x^3y^2) (2X^4y) When I multiply x^3*x^4= X^12 Y^2*Y=y^2 do I still mulity the 3 and the 2 together ? Would the answer be 6x^12Y^2? Thank you       Log On


   

Question 711020: (3x^3y^2) (2X^4y)
When I multiply x^3*x^4= X^12
Y^2*Y=y^2
do I still mulity the 3 and the 2 together ?
Would the answer be 6x^12Y^2?
Thank you
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You do NOT multiply the exponents. You add them.

For x: 3+4 = 7

For y: 2+1 = 3

So the final answer is really 6x%5E7y%5E3