You can put this solution on YOUR website! y varies jointly as m and the square of n and inversly as p
y=15 when m=2, n=1, and p=6. Find y when m=3, n=4 and p=10
For all proportion problems, start with this:
Varying "directly" or product of "jointlys" or 1 if none
quantity = k · ----------------------------------------------------------
inversely variable or product of "inverselys" or 1 if none
In this problem the varying quantity is y.
the "jointlys" are m and n². We have one inversely, p. So we have m·n²
on top and p on the bottom:
y = k·
>>...y=15 when m=2, n=1, and p=6....<<
Substitute these values:
15 = k·
15 = k·
15 = k·
15 = k·
Multiply both sides by 3
45 = k
Now substitute 45 for k in the first equation:
y = 45·
>>...Find y when m=3, n=4 and p=10...<<
Substitute those values
y = 45·
y = 45·
y = 216
Edwin
