SOLUTION: {{{ 2^x*2^(x+1)=4^(x^2+x) }}}

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: {{{ 2^x*2^(x+1)=4^(x^2+x) }}}      Log On


   

Question 630605: +2%5Ex%2A2%5E%28x%2B1%29=4%5E%28x%5E2%2Bx%29+
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
2^x*2^(x+1)=4^(x^2+x)
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2^(2x+1) = 2^(2x^2+2x)
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2x+1 = 2x^2 + 2x
2x^2 = 1
x^2 = 1/2
x = sqrt(1/2) or x = -sqrt(1/2)
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Cheers,
Stan H.
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