Question 605684: Write the following expression as a sum and/or difference of logarithms
log((cube root x^2+1)/(x^2-1)) Answer by lawdej(58) (Show Source):
You can put this solution on YOUR website! log((cube root x^2+1)/(x^2-1))
=log(cube root x^2+1)-log(x^2-1)=log(cube root x^2+1)-log((x-1)(x+1))
=log(cube root x^2+1)-(log(x-1)+log(x+1))