SOLUTION: I'm seriously going to fail this: Need help please :) The questions is find the solution set for e^(3x+2)=55

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: I'm seriously going to fail this: Need help please :) The questions is find the solution set for e^(3x+2)=55      Log On


   



Question 604632: I'm seriously going to fail this: Need help please :)
The questions is find the solution set for e^(3x+2)=55

Found 2 solutions by jim_thompson5910, lwsshak3:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
e%5E%283x%2B2%29=55

ln%28e%5E%283x%2B2%29%29=ln%2855%29

%283x%2B2%29ln%28e%29=ln%2855%29

%283x%2B2%29%281%29=ln%2855%29

3x%2B2=ln%2855%29

3x=ln%2855%29-2

x=%28ln%2855%29-2%29%2F3

So the exact solution is x=%28ln%2855%29-2%29%2F3 which approximates to x=0.669

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
find the solution set for
e^(3x+2)=55
take log of both sides
using calculator
(3x+2)*lne=ln55
lne=1 (log of base=1)
3x+2=ln55
3x=ln55-2
x=(ln55-2)/3
x≈.669