SOLUTION: [x-4/x^2][x^4/x^2-3x-4]= a.x^6/x+1 b.x^6/x-4 c.x^2/x+1 d.x^2/x-4

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: [x-4/x^2][x^4/x^2-3x-4]= a.x^6/x+1 b.x^6/x-4 c.x^2/x+1 d.x^2/x-4       Log On


   

Question 603731: [x-4/x^2][x^4/x^2-3x-4]=
a.x^6/x+1
b.x^6/x-4
c.x^2/x+1
d.x^2/x-4
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
[x-4/x^2][x^4/x^2-3x-4]=
a.x^6/x+1
b.x^6/x-4
c.x^2/x+1
d.x^2/x-4
**
[x-4/x^2][x^4/x^2-3x-4]
=[x-4/x^2][x^4/(x-4)(x+1)]
x^2 and (x-4) cancel out
=x^2/(x+1) (ans c.)