SOLUTION: is the answer to 2^(x+1)=5^(1-2x) x=(ln 2+ln 5)/(ln 2-5ln2)?

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Question 532358: is the answer to 2^(x+1)=5^(1-2x) x=(ln 2+ln 5)/(ln 2-5ln2)?
Found 2 solutions by stanbon, KMST:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
is the answer to 2^(x+1)=5^(1-2x) x=(ln 2+ln 5)/(ln 2-5ln2)?
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2^(x+1)=5^(1-2x)
(x+1)*ln(2) = (1-2x)*ln(5)
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x*ln(2) + ln(2) = ln(5) -2ln(5)x
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Get the "x" terms together.
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x (ln(2)+2ln(5)) = ln(5)-ln(2)
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x(ln[2*25)) = ln(5/2)
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x = ln(5/2)/ln(50)
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x = 0.2342
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Cheers,
Stan H.
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Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
2%5E%28x%2B1%29=5%5E%281-2x%29 means
%28x%2B1%29ln%282%29=%281-2x%29ln%285%29
Applying the distributive property
x%2Aln%282%29%2Bln%282%29=ln%285%29-2x%2Aln%285%29
Then
x%2Aln%282%29%2B2x%2Aln%285%29=ln%285%29-ln%282%29
x%28ln%282%29%2B2%2Aln%285%29%29=ln%285%29-ln%282%29
and
x=%28ln%285%29-ln%282%29%29%2F%28ln%282%29%2B2%2Aln%285%29%29%3E0
That's different from