SOLUTION: One more for verification purposes:
IF something increases by 40% every 6 months what is the 1-year % increase?
Let S= something
S=(1+.40)^12 = S(1.40)^12 = S(56.59) = S
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: One more for verification purposes:
IF something increases by 40% every 6 months what is the 1-year % increase?
Let S= something
S=(1+.40)^12 = S(1.40)^12 = S(56.59) = S
Log On
Question 432553: One more for verification purposes:
IF something increases by 40% every 6 months what is the 1-year % increase?
Let S= something
S=(1+.40)^12 = S(1.40)^12 = S(56.59) = S increased by 56.59% in 1 year.
Hi
IF something increases by 40% every 6 months what is the 1-year % increase
After 1st 6mos, S would be S + .40S OR 1.40S
after 2nd 6mos. S would be [(1.40S) + .40*(1.40S)] OR 1.96S or a 96% increase.