SOLUTION: can you help me with this ..
solve for x : log5(10x+4) - log5 2 = 1/2log5 49 + 2log5 4
ALL THE 5'S ARE ACTUALLY SMALL, i just didnt no how to do it on my keybored, thanks for t
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: can you help me with this ..
solve for x : log5(10x+4) - log5 2 = 1/2log5 49 + 2log5 4
ALL THE 5'S ARE ACTUALLY SMALL, i just didnt no how to do it on my keybored, thanks for t
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Question 422285: can you help me with this ..
solve for x : log5(10x+4) - log5 2 = 1/2log5 49 + 2log5 4
ALL THE 5'S ARE ACTUALLY SMALL, i just didnt no how to do it on my keybored, thanks for the help! Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! solve for x : log5(10x+4) - log5(2) = 1/2log5(49) + 2log5(4)
:
1/2 is the square root exponent, return the exponent to inside the radical
Which is
log5(5x+2) = log5(7) + log(16)
:
log5(5x+2) = log5(7*16)
log5(5x+2) = log5(112)
:
therefore, we can say:
5x + 2 = 112
5x = 112 - 2
5x = 110
x =
x = 22
;
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