SOLUTION: (1/16)^x+1=(1/8)^2x-1

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: (1/16)^x+1=(1/8)^2x-1      Log On


   

Question 398983: (1/16)^x+1=(1/8)^2x-1
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

%281%2F16%29%5E%28x%2B1%29=%281%2F8%29%5E%282x-1%29

%281%2F2%29%5E%284%28x%2B1%29%29=%281%2F2%29%5E%283%282x-1%29%29

    4(x+1) = 3(2x-1)

   4x + 4 = 6x - 3

        7 = 2x

        7/2 = x