SOLUTION: 4^(2x+7)=32^(x+3)
Algebra
->
Exponential-and-logarithmic-functions
-> SOLUTION: 4^(2x+7)=32^(x+3)
Log On
Algebra: Exponent and logarithm as functions of power
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Exponential-and-logarithmic-functions
Question 389863
:
4^(2x+7)=32^(x+3)
Answer by
stanbon(75887)
(
Show Source
):
You can
put this solution on YOUR website!
4^(2x+7)=32^(x+3)
----
[2^2]^(2x+7) = [2^5]^(x+3)
----
2^(4x+14) = 2^(5x+15)
----
4x+14 = 5x+15
x = -1
=======
Cheers,
Stan H.