SOLUTION: Sovling inequalities: 2^(3n-1)>=(1/8)^n

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Question 386744: Sovling inequalities: 2^(3n-1)>=(1/8)^n
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
2%5E%283n-1%29%3E=%281%2F8%29%5En. This inequality is the same as 2%5E%283n-1%29%3E=2%5E%28-3n%29. Now take the base-2 logarithm of both sides of the inequality, to get
3n+-+1+%3E=+-3n. This inequality is true because we know the base-2 logarithm function is an INCREASING function. Hence, 6n+%3E=+1, or n+%3E=+1%2F6.