SOLUTION: .1=.159+.118log x i know x=.316 but i don't know how they got that. could you explain? thanks for the help!

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: .1=.159+.118log x i know x=.316 but i don't know how they got that. could you explain? thanks for the help!      Log On


   

Question 297355: .1=.159+.118log x
i know x=.316 but i don't know how they got that. could you explain?
thanks for the help!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
0.1=0.159%2B0.118log%28%28x%29%29 Start with the given equation.


0.1-0.159=0.118log%28%28x%29%29 Subtract 0.159 from both sides.


-0.059=0.118log%28%28x%29%29 Combine like terms.


-0.059%2F0.118=log%28%28x%29%29 Divide both sides by 0.118.


-0.5=log%28%28x%29%29 Divide.


x=10%5E%28-0.5%29 Convert to exponential form


x=0.316227766 Use a calculator to compute the right side.


So the answer is roughly x=0.316