SOLUTION: Solve Equation Problem: 16^-x+2=8 -x+2=log16(8) Have I started this correctly, I'm very confused!!

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Solve Equation Problem: 16^-x+2=8 -x+2=log16(8) Have I started this correctly, I'm very confused!!       Log On


   



Question 276310: Solve Equation
Problem: 16^-x+2=8
-x+2=log16(8)

Have I started this correctly, I'm very confused!!

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
As long as the entire expression, -x+2, was the exponent of 16, then you have started correctly. To finish solving for x we...
Add -2 to each side:
-x+=+-2+%2B+log%2816%2C+%288%29%29
and multiply both sides by -1:
x+=+2+-+log%2816%2C+%288%29%29
In many cases we would stop here if we wanted an exact answer. But since both 16 and 8 are powers of 2, we can simplify the logarithm. If you're clever you might be able to figure out what power of 16 results in 8. If not then we can use the base conversion formula, log%28a%2C+%28p%29%29+=+log%28b%2C+%28p%29%29%2Flog%28b%2C+%28a%29%29, to convert the base 16 log into an expression of base 2 logs:
x+=+2+-+%28log%282%2C+%288%29%29%2Flog%282%2C+%2816%29%29%29
Since 2%5E3+=+8 and 2%5E4+=+16, the numerator is 3 and the denominator is 4. (This means 16%5E%283%2F4%29+=+8):
x+=+2+-+3%2F4
All we have left is to subtract:
x+=+8%2F4+-+3%2F4
x+=+5%2F4