SOLUTION: If f(x) = log2x, find f(16) 16=log 2x 2^16 =65,536 is this right

Question 253217: If f(x) = log2x, find f(16)
16=log 2x
2^16 =65,536
is this right
Found 2 solutions by drk, Earlsdon:
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
I assume you mean the 2 is the base.
F(x) = log_2(x)
We want to find the value of F when x = 16. Where you see x, replace it with 16.
F(16) = log_2(16)
what is the value of log_2(16)?
2^y = 16
y = 4.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Not quite!
If find
Recall that the definition of the logarithm of a number is the "power" to which the "base" must be raised to equal that number. Or which can be expressed as:
In this problem, the 'base' is given as 2, and to find f(16) you must replace the x in the f(x) of the problem with 16, so now you have:

Let's rewrite the problem a bit replacing wth :
, then according to the above definition, we can write this as (--->:
Substitute
Now since the bases are equal, the exponents must be equal, so...
but so...

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