SOLUTION: Kaleah1 needs help in solving word problem below:
Upstream, downstream. Junior's boat will go 15 miles per hour in still water. If he can go 12 miles downstream in the same amo
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-> SOLUTION: Kaleah1 needs help in solving word problem below:
Upstream, downstream. Junior's boat will go 15 miles per hour in still water. If he can go 12 miles downstream in the same amo
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Question 203001This question is from textbook Elementary & Intermediate Algebra
: Kaleah1 needs help in solving word problem below:
Upstream, downstream. Junior's boat will go 15 miles per hour in still water. If he can go 12 miles downstream in the same amount of time as it takes to go 9 miles upstream, then what is the speed of the current? This question is from textbook Elementary & Intermediate Algebra
You can put this solution on YOUR website! Junior's boat will go 15 miles per hour in still water. If he can go 12 miles downstream in the same amount of time as it takes to go 9 miles upstream, then what is the speed of the current?
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Downstream DATA:
distance = 12 miles ; rate = 15+c mph ; time = d/r = 12/(15+c) hrs.
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Upstream DATA:
distance = 9 miles ; rate = 15-c mph ; time = d/r = 9/(15-c) hrs.
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Equation:
time up = time down
9/(15-c) = 12/(15+c)
Cross-multiply
9(15+c) = 12(15-c)
135 + 9c = 180 - 12c
21c = 45
c = 2.5 mph (speed of the current)
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Cheers,
Stan H.
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