SOLUTION: Can someone help me with these? The directions are as follows: Use the table of logarithms to calculate the answers: 1) log 7.83 = 2) log .068 = 3) antilog 0.3

Question 202463: Can someone help me with these? The directions are as follows:
Use the table of logarithms to calculate the answers:

1) log 7.83 =

2) log .068 =

3) antilog 0.3814 =

4) antilog (8.3174 - 10) =

Thanks! ~Sarah
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
I don't have a table of logarithms, but I have a calculator.
It won't help you looking up the answers in the table, but it will provide the answers.
these are all presumably to the base 10.
1) log 7.83 = .893761762
2) log .068 = -1.167491087
3) antilog 0.3814 = 2.40657832
4) antilog (8.3174 - 10) = antilog (-1.6826) = .020768255
antilog should be the inverse function of the log.
inverse function of the log is the exponent.
if y = log(x), then 10^y = x
example:
2 = log(100), then 10^2 = 100
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in number 3, you have:
log (x) = .3814 which implies that 10^.3814 = x which means that x = 2.40657832.
this happens to be true because 10^.3814 = 2.40657832.
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in number 4, you have:
log(x) = (8.3174 - 10 ) = (-1.6826) which implies that 10^(-1.6826) = .020768255.
this happens to be true because 10^(-1.6826) = .020768255.
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not sure if I got you the answers you wanted.
anti-log, however, is the inverse of the log, and it was explained as being the exponential form.
logs are defined as follows:
if and only if
in your problems, the base was assumed to be 10 since it wasn't mentioned. this is the standard way of expressing logs. no base mentioned, base = 10.
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