SOLUTION: solve: log3^(x-3)+log3^(x+2)=log3^6

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Question 198549: solve:
log3^(x-3)+log3^(x+2)=log3^6
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Apply "log rules":
log3(x-3)+log3(x+2)=log3(6)
log3(x-3)(x+2)=log3(6)
(x-3)(x+2)=6
x^2+2x-3x-6 = 6
x^2-x-12 = 0
(x-4)(x+3) = 0
x = {-3,4}
We can toss out the negative solution leaving us with:
x = 4