You can put this solution on YOUR website! please graph this logarithmic function.. or give me the points.:)
y=log[4](x+1)
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Do you know the vertical asymptote of y = log(x) is at x = 0?
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Do you see that your equation moves that graph one unit to the left
because is has the (x+1) replacing "x" in the log form?
So you have a vertical asymptote at x = -1
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Can you follow this?
Since y = log[4](x+1)
x+1 = 4^y
x = (4^y) -1
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So if y = 0, x will equal 0
The x and the y intercept will be (0,0)
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Does that give you enough information to sketch the graph?
It should look like this:
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Cheers,
Stan H.
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