SOLUTION: solve LN(x^2+10)>LNx+LN7

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: solve LN(x^2+10)>LNx+LN7      Log On


   



Question 198274: solve
LN(x^2+10)>LNx+LN7

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
ln(x^2+10)>ln(x)+ln(7)
e^ln(x^2+10)>e^ln(7x)
x^2+10>7x
x^2-7x+10=0 Use an equal sign instead of inequality.
(x-5)(x-2)=0
x=5, x=2 These are inflection points.
Since the coefficient of x^2 is positive (+1) the graph has a minimum and the equation is negative when 5>x>2
.
Ed
.
graph%28500%2C500%2C-10%2C10%2C-10%2C10%2Cx%5E2-7x%2B10%29