SOLUTION: Ok so I have the solutions to the problem...but I keep coming up with the wrong answer and I don't understand why. Here's the problem:
{{{16^(d-4)=3^(3-d)}}}
The instructions
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: Ok so I have the solutions to the problem...but I keep coming up with the wrong answer and I don't understand why. Here's the problem:
{{{16^(d-4)=3^(3-d)}}}
The instructions
Log On
Question 195522: Ok so I have the solutions to the problem...but I keep coming up with the wrong answer and I don't understand why. Here's the problem:
The instructions are to solve each equation or inequality. Round to four decimal places.
Here's what I've tried:
The book says that the solution is 3.716 Answer by Edwin McCravy(20060) (Show Source):
You went wrong on the rule of logarithms that says
You move the entire exponent in front of the log:
Take logs of both sides
Now use the rule that you missed. Move the
(d-4) in parentheses in front of the log on
the left, and move the (3-d) in parentheses
in front of the log on the right, and
get:
Now here is something that might make it
easier for you, since it is easier to work
with single letters than logs. So I suggest
doing this:
Let the letter A = log(16)
Let the letter B = log(3)
Substitute the letter A for log(16) and
substitute the letter B for log(3)
Now get your calculator and find
A = log(16) = 1.204119983
B = log(3) = .4771212547
Substitute those:
Edwin
