SOLUTION: The problem directions state: Solve the equation. Check for extraneous solutions. 49.) 2ln(-x)+7= 14 I understand you remove 7 from both sides, but I am wondering how I chan

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: The problem directions state: Solve the equation. Check for extraneous solutions. 49.) 2ln(-x)+7= 14 I understand you remove 7 from both sides, but I am wondering how I chan      Log On


   

Question 186562This question is from textbook
: The problem directions state: Solve the equation. Check for extraneous solutions.
49.) 2ln(-x)+7= 14
I understand you remove 7 from both sides, but I am wondering how I change this particular problem into exponential form and what is the set-up for exponential form! Thanks! This question is from textbook

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
2%2Aln%28-x%29+%2B+7+=+14
Subtract 7 from both sides
2%2Aln%28-x%29+=+7
ln%28-x%29+=+7%2F2
-x+=+e%5E%287%2F2%29
First of all, any number raised to any power cannot
be negative, so x+%3C+0
By my calculator,
x+=+-33.115