SOLUTION: factor the trinomial x squared minus 5x minus 6 x2-5x-6

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Question 183435: factor the trinomial
x squared minus 5x minus 6
x2-5x-6

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at the expression x%5E2-5x-6, we can see that the first coefficient is 1, the second coefficient is -5, and the last term is -6.


Now multiply the first coefficient 1 by the last term -6 to get %281%29%28-6%29=-6.


Now the question is: what two whole numbers multiply to -6 (the previous product) and add to the second coefficient -5?


To find these two numbers, we need to list all of the factors of -6 (the previous product).


Factors of -6:
1,2,3,6
-1,-2,-3,-6


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -6.
1*(-6)
2*(-3)
(-1)*(6)
(-2)*(3)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -5:


First NumberSecond NumberSum
1-61+(-6)=-5
2-32+(-3)=-1
-16-1+6=5
-23-2+3=1



From the table, we can see that the two numbers 1 and -6 add to -5 (the middle coefficient).


So the two numbers 1 and -6 both multiply to -6 and add to -5


Now replace the middle term -5x with x-6x. Remember, 1 and -6 add to -5. So this shows us that x-6x=-5x.


x%5E2%2Bhighlight%28x-6x%29-6 Replace the second term -5x with x-6x.


%28x%5E2%2Bx%29%2B%28-6x-6%29 Group the terms into two pairs.


x%28x%2B1%29%2B%28-6x-6%29 Factor out the GCF x from the first group.


x%28x%2B1%29-6%28x%2B1%29 Factor out 6 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28x-6%29%28x%2B1%29 Combine like terms. Or factor out the common term x%2B1

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Answer:


So x%5E2-5x-6 factors to %28x-6%29%28x%2B1%29.


Note: you can check the answer by FOILing %28x-6%29%28x%2B1%29 to get x%5E2-5x-6 or by graphing the original expression and the answer (the two graphs should be identical).