SOLUTION: (1/3)^2-x=27^3+x

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Question 181203: (1/3)^2-x=27^3+x
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
(1/3)^2-x=27^3+x
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I'll assume the exponents are (2-x) and (3+x).
(1/3)^(2-x) = 3^(x-2)
And, 27^(3+x) = 3^(9+3x) (27 = 3^3)
So,
3^(x-2) = 3^(3x+9)
x-2 = 3x+9
2x = -11
x = -11/2

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(1/3)^(2-x)=27^(3+x)
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3^(-(2-x)) = 3^(3(3+x))
3^(-2+x) = 3^(9+3x)
-2+x = 9+3x
2x = -11
x = -11/2
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Cheers,
Stan H.