SOLUTION: Explain the relationship, if any, among the following equations. 16^2=x and 16=logx^2

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Explain the relationship, if any, among the following equations. 16^2=x and 16=logx^2      Log On


   



Question 170173: Explain the relationship, if any, among the following equations.
16^2=x and 16=logx^2

Found 3 solutions by Earlsdon, Alan3354, stanbon:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
1) 16%5E2+=+x So...
x+=+256
2) 16+=+log%28x%5E2%29
16+=+2log%28x%29
8+=+log%28x%29 so...
x+=+10%5E8
x+=+100000000
I don't see a relationship between the two!

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Explain the relationship, if any, among the following equations.
16^2=x and 16=logx^2
---------------
x = 16^2 = 256.
x^2 = 65536
2^16 = 65536
log%282%2C65536%29+=+16
You didn't specify that base, but only 2 will fit. If it's not base 2, then both statements cannot be true.


Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Explain the relationship, if any, among the following equations.
16^2=x and 16=logx^2
================
1st: x = 256
---------------
2nd: 16 = 2logx
logx = 8
x = 10^8
x = 10,000,000
------------------
Cheers,
Stan H.