SOLUTION: OK so i need to know how one would go about answering {{{ 3^x=5^(x+2) }}}. i've tried going {{{ log (3,3^x)= log (3,5^(x+2))}}} simplified to {{{x=log (3,5^(x+2))}}} then i did {

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: OK so i need to know how one would go about answering {{{ 3^x=5^(x+2) }}}. i've tried going {{{ log (3,3^x)= log (3,5^(x+2))}}} simplified to {{{x=log (3,5^(x+2))}}} then i did {      Log On


   

Question 162923: OK so i need to know how one would go about answering +3%5Ex=5%5E%28x%2B2%29+.
i've tried going +log+%283%2C3%5Ex%29=+log+%283%2C5%5E%28x%2B2%29%29 simplified to x=log+%283%2C5%5E%28x%2B2%29%29 then i did x=%28log+%285%2C5%5E%28x%2B2%29%29%29%2F%28log+%285%2C3%29%29 simplified to x=%28x%2B2%29%2F%28log+%285%2C3%29%29 but then i'm stuck
Answer by Anthea Lawn(22) About Me  (Show Source):
You can put this solution on YOUR website!
You are already on the right lines :
Take the logs of both sides :
x log 3 = (x + 2) log 5
x log 3 = x log 5 + 2 log 5
x(log 3 - log 5) = 2 log 5
x = 2 log 5/(log3 - log 5) = -6.301