SOLUTION: How do I factor this trinomoial: 5x^2+16x+3

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Question 148757This question is from textbook
: How do I factor this trinomoial:
5x^2+16x+3
This question is from textbook

Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

5x%5E2%2B16x%2B3 Start with the given expression.


Looking at the expression 5x%5E2%2B16x%2B3, we can see that the first coefficient is 5, the second coefficient is 16, and the last term is 3.


Now multiply the first coefficient 5 by the last term 3 to get %285%29%283%29=15.


Now the question is: what two whole numbers multiply to 15 (the previous product) and add to the second coefficient 16?


To find these two numbers, we need to list all of the factors of 15 (the previous product).


Factors of 15:
1,3,5,15
-1,-3,-5,-15


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 15. For instance, 1%2A15=15, 3%2A5=15, etc.


Since 15 is positive, this means that either
a) both factors are positive, or...
b) both factors are negative.


Now let's add up each pair of factors to see if one pair adds to the middle coefficient 16:


First NumberSecond NumberSum
1151+15=16
353+5=8
-1-15-1+(-15)=-16
-3-5-3+(-5)=-8



From the table, we can see that the two numbers 1 and 15 add to 16 (the middle coefficient).


So the two numbers 1 and 15 both multiply to 15 and add to 16


Now replace the middle term 16x with x%2B15x. Remember, 1 and 15 add to 16. So this shows us that x%2B15x=16x.


5x%5E2%2Bhighlight%28x%2B15x%29%2B3 Replace the second term 16x with x%2B15x.


%285x%5E2%2Bx%29%2B%2815x%2B3%29 Group the terms into two pairs.


x%285x%2B1%29%2B%2815x%2B3%29 Factor out the GCF x from the first group.


x%285x%2B1%29%2B3%285x%2B1%29 Factor out 3 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28x%2B3%29%285x%2B1%29 Combine like terms. Or factor out the common term 5x%2B1

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Answer:


So 5x%5E2%2B16x%2B3 factors to %28x%2B3%29%285x%2B1%29.


Note: you can check the answer by FOILing %28x%2B3%29%285x%2B1%29 to get 5x%5E2%2B16x%2B3 or by graphing the original expression and the answer.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
factor this trinomial:
5x^2+16x+3
-----------------
Using the AC Method of Factoring:
Find two numbers whose product is 3*5 = 15
and whose sum is 16:
The numbers are 15 and 1
Rewrite the problem as follows:
5x^2+15x+x+3
Factor the 1st two and the last two terms seperately:
5x(x+3) + (x+3)
Factor again:
(x+3)(5x+1)
===============================
Cheers,
Stan H.