SOLUTION: solve for b.
log( b, 9 )=2/3
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Question 139320: solve for b.
log( b, 9 )=2/3
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve for b.
log( b, 9 )=2/3
------------------
Exponential Form:
b^(2/3) = 9
Raise both sides to the (3/2) power to get:
b = 9^(3/2) = 3^3 = 27
============================
Cheers,
Stan H.
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