SOLUTION: Use synthetic division grid to analyze and graph the function. P(x) = 9x^4 – 6x^3 – 26x^2 + 18 x - 3

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Use synthetic division grid to analyze and graph the function. P(x) = 9x^4 – 6x^3 – 26x^2 + 18 x - 3       Log On


   



Question 135713: Use synthetic division grid to analyze and graph the function.
P(x) = 9x^4 – 6x^3 – 26x^2 + 18 x - 3

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Any rational zero can be found through this equation

where p and q are the factors of the last and first coefficients


So let's list the factors of 3 (the last coefficient):



Now let's list the factors of 9 (the first coefficient):



Now let's divide each factor of the last coefficient by each factor of the first coefficient









Now simplify

These are all the distinct rational zeros of the function that could occur






To save time, I'm only going to use synthetic division on the possible zeros that are actually zeros of the function.
Otherwise, I would have to use synthetic division on every possible root (there are 8 possible roots, so that means there would be at most 8 synthetic division tables).
However, you might be required to follow this procedure, so this is why I'm showing you how to set up a problem like this


If you're not required to follow this procedure, simply use a graphing calculator to find the roots


It turns out that 1%2F3 is actually a root. So our test zero is 1/3


Now set up the synthetic division table by placing the test zero in the upper left corner and placing the coefficients of the numerator to the right of the test zero.
1/3|9-6-2618-3
|

Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 9)
1/3|9-6-2618-3
|
9

Multiply 1/3 by 9 and place the product (which is 3) right underneath the second coefficient (which is -6)
1/3|9-6-2618-3
|3
9

Add 3 and -6 to get -3. Place the sum right underneath 3.
1/3|9-6-2618-3
|3
9-3

Multiply 1/3 by -3 and place the product (which is -1) right underneath the third coefficient (which is -26)
1/3|9-6-2618-3
|3-1
9-3

Add -1 and -26 to get -27. Place the sum right underneath -1.
1/3|9-6-2618-3
|3-1
9-3-27

Multiply 1/3 by -27 and place the product (which is -9) right underneath the fourth coefficient (which is 18)
1/3|9-6-2618-3
|3-1-9
9-3-27

Add -9 and 18 to get 9. Place the sum right underneath -9.
1/3|9-6-2618-3
|3-1-9
9-3-279

Multiply 1/3 by 9 and place the product (which is 3) right underneath the fifth coefficient (which is -3)
1/3|9-6-2618-3
|3-1-93
9-3-279

Add 3 and -3 to get 0. Place the sum right underneath 3.
1/3|9-6-2618-3
|3-1-93
9-3-2790

Since the last column adds to zero, we have a remainder of zero. This means 3x-1 is a factor of 9x%5E4+-+6x%5E3+-+26x%5E2+%2B+18x+-+3

Now lets look at the bottom row of coefficients:

The first 4 coefficients (9,-3,-27,9) form the quotient

9x%5E3+-+3x%5E2+-+27x+%2B+9


Notice in the denominator 3x-1, the x term has a coefficient of 3, so we need to divide the quotient by 3 like this:
%289x%5E3+-+3x%5E2+-+27x+%2B+9%29%2F2=3x%5E3+-+x%5E2+-+9x+%2B+3

So %289x%5E4+-+6x%5E3+-+26x%5E2+%2B+18x+-+3%29%2F%283x-1%29=3x%5E3+-+x%5E2+-+9x+%2B+3

You can use this online polynomial division calculator to check your work

Basically 9x%5E4+-+6x%5E3+-+26x%5E2+%2B+18x+-+3 factors to %283x-1%29%283x%5E3+-+x%5E2+-+9x+%2B+3%29

Now lets break 3x%5E3+-+x%5E2+-+9x+%2B+3 down further


Once again through the rational root theorem, we find that 1%2F3 is another root (since it occurs twice)



So once again our test zero is 1/3


Now set up the synthetic division table by placing the test zero in the upper left corner and placing the coefficients of the numerator to the right of the test zero.
1/3|3-1-93
|

Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 3)
1/3|3-1-93
|
3

Multiply 1/3 by 3 and place the product (which is 1) right underneath the second coefficient (which is -1)
1/3|3-1-93
|1
3

Add 1 and -1 to get 0. Place the sum right underneath 1.
1/3|3-1-93
|1
30

Multiply 1/3 by 0 and place the product (which is 0) right underneath the third coefficient (which is -9)
1/3|3-1-93
|10
30

Add 0 and -9 to get -9. Place the sum right underneath 0.
1/3|3-1-93
|10
30-9

Multiply 1/3 by -9 and place the product (which is -3) right underneath the fourth coefficient (which is 3)
1/3|3-1-93
|10-3
30-9

Add -3 and 3 to get 0. Place the sum right underneath -3.
1/3|3-1-93
|10-3
30-90

Since the last column adds to zero, we have a remainder of zero. This means 3x-1 is a factor of 3x%5E3+-+x%5E2+-+9x+%2B+3

Now lets look at the bottom row of coefficients:

The first 3 coefficients (3,0,-9) form the quotient

3x%5E2+-+9


Notice in the denominator 3x-1, the x term has a coefficient of 3, so we need to divide the quotient by 3 like this:
%283x%5E2+-+9%29%2F2=x%5E2+-+3

So %283x%5E3+-+x%5E2+-+9x+%2B+3%29%2F%283x-1%29=x%5E2+-+3

You can use this online polynomial division calculator to check your work



So this means that 9x%5E4+-+6x%5E3+-+26x%5E2+%2B+18x+-+3 factors to %28x%5E2-3%29%283x-1%29%5E2


This tells us that the zeros are x=-sqrt%283%29, x=sqrt%283%29, and x=1%2F3 (with a multiplicity of 2)


So we can now graph the function by drawing a curve through the zeros



+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+9x%5E4+-+6x%5E3+-+26x%5E2+%2B+18x+-+3%29+